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4 March, 03:44

What volume is occupied by 0.675 mol of CO2 at 226.2 K and 861 mmHg?

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  1. 4 March, 04:58
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    PV=nRT

    V=nRT/P

    n=0.675 mol

    T=226.2 K

    P=861 mm Hg≈114790 Pa

    R=8.31 J / (mol*K)

    V=0.675*8.31*226.2/114790=0.01105 m³=11.05 L
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