You want to prepare 50cm of 0.1m NaoH from exactly 50% (wt/wt) NaoH solution. what volume of the 50% solution is required

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Chemistry

Goonie

24 December, 01:07

You want to prepare 50cm of 0.1m NaoH from exactly 50% (wt/wt) NaoH solution. what volume of the 50% solution is required

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Darrell Ayala · Answer 1

We want 50 cm^3 of 0.1 M NaOH, i. e we need (50 ml / 1000 mL) * (0.1 mole)

= 0.005 moles of NaOH >>> (1)

we have 50 % (wt/wt) NaOH, i. e we have 50 g NaOH in 100 Solution

= 50 g / 100 g solution, to convert this to molarity (mol/L) we will do that:

(50g NaOH * 1.5253 density of solution (g/ml) * 1000) / (40 M. wt NaOH (g/mol) * 100g Solution) = 19.07 mol/L >>> (2)

From (1) and (2), ∴ 0.005 moles of NaOH = 19.07 mol/L

∴ the Volume (L) of 50% of solution = 0.005 moles / 19.07 mol/L

= 2.6 * 10 ^ - 4 L = 0.26 mL