When a solution of barium nitrate and a solution of copper (II) sulfate are mixed, a chemical reaction produces solid barium sulfate, which sinks to the bottom, and a solution of copper (II) nitrate. Suppose some barium nitrate is dissolved in 120.00 g of water and 8.15 g of copper (II) sulfate is dissolved in 75.00 g of water. The solutions are poured together, and a white solid forms. After the solid is filtered off, it is found to have a mass of 10.76 g. The mass of the solution that passed through the filter is 204.44 g. What mass of barium nitrate was used in the reaction?

Question

Chemistry

Luciana Moss

17 October, 12:46

When a solution of barium nitrate and a solution of copper (II) sulfate are mixed, a chemical reaction produces solid barium sulfate, which sinks to the bottom, and a solution of copper (II) nitrate. Suppose some barium nitrate is dissolved in 120.00 g of water and 8.15 g of copper (II) sulfate is dissolved in 75.00 g of water. The solutions are poured together, and a white solid forms. After the solid is filtered off, it is found to have a mass of 10.76 g. The mass of the solution that passed through the filter is 204.44 g. What mass of barium nitrate was used in the reaction?

+5

Answers (1)

Know the Answer?

Nicole · Answer 1

The total mass of the products is 10.76 g + 204.44 g = 215.20 g.

The masses of all the reactants but one are known so,

215.20 g - 120.00 g - 8.15 g - 75.00 g = 12.05 g

12.05 g is the mass of the unweighed barium nitrate.