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20 May, 20:33

If 1.20 moles of an ideal gas occupy a volume of 18.2 L at a pressure of 1.80 atm, what is the temperature of the gas, in degrees Celsius?

-125°C

59.5°C

273°C

32°C

+1
Answers (1)
  1. 20 May, 23:01
    0
    The equation that we will use to solve this problem is:

    PV = nRT where:

    P is the pressure of gas = 1.8 atm

    V is the volume of gas = 18.2 liters

    n is the number of moles of gas = 1.2 moles

    R is the gas constant = 0.0821

    T is the temperature required (calculated in kelvin)

    Using these values to substitute in the equation, we find that:

    (1.8) (18.2) = (1.2) (0.0821) (T)

    T = 332.5 degree kelvin

    The last step is to convert the degree kelvin into degree celcius:

    T = 332.5 - 273 = 59.5 degree celcius
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