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31 December, 08:25

Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively? express the molar concentrations numerically.

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  1. 31 December, 09:50
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    Missing in your question:

    Concentration by (M):

    Xy: y: X

    initial 0.2 0.3 0.3

    change + X - X - X

    equilibrim (0.2+x) (0.3-x) (0.3-x)

    according to Kc formula: when Kc = 0.2

    Kc = [XY]/[X]*[Y]

    0.2 = (0.2+x) / (0.3-x) * (0.3-x)

    0.2 = (0.2+x) / (0.3-x) ^2 by solving this equation

    0.2 * (0.3-x) ^2 = 0.2+x

    0.2 * (0.09-0.6x+x^2) = 0.2 + x

    0.0018 - 0.12 X + 0.2X^2 = 0.2 + X

    0.2X^2 - 1.12 X - 0.1982 = 0

    ∴X = 0.17

    ∴[XY] = 0.2 + 0.17 = 0.37 m

    ∴[X] = 0.3 - 0.17 = 0.13 m

    ∴[y] = 0.3 - 0.17 = 0.13 m
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