The heat of combustion of ethane c2h6 is 1560 kj mol. what is the heat of combustion of ethane, in kj per gram

51.88 kJ / g

Solution:

As we know 1 mole of ethane equals 30.07 g as,

C₂H₆ = (12.01) ₂ + (1.008) ₆

= 24.02 + 6.048

1 mole = 30.068 g

Now, As heat of combustion of ethane C₂H₆ is,

= 1560 kJ / mol

Substituting value of mole by gram,

= 1560 kJ / 30.068 g

= 51.88 kJ / g