How many molecules of glucose, C6H12O6, can be "burned" biologically when 283.2 grams of oxygen is a available?

Question

Chemistry

Myles Leonard

7 November, 09:39

How many molecules of glucose, C6H12O6, can be "burned" biologically when 283.2 grams of oxygen is a available?

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Answers (1)

Know the Answer?

Ivan Fields · Answer 1

Answer is: 8,85·10²³ molecules of glucose.

Chemical reaction: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.

m (C₆H₁₂O₆) = ?

m (O₂) = 283,2 g.

n (O₂) = m (O₂) : M (O₂).

n (O₂) = 83,2 g : 32 g/mol.

n (O₂) = 8,85 mol.

from reaction: n (O₂) : n (C₆H₁₂O₆) = 6 : 1.

n (C₆H₁₂O₆) = 1,475 mol.

N (C₆H₁₂O₆) = n · Na

N (C₆H₁₂O₆) = 1,475 mol · 6·10²³ 1/mol = 8,85·10²³.

Na - Avogadro number.