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17 November, 07:28

What is the hydroxide-ion concentration in a solution formed by combining 200. ml of 0.16 m hcl with 300. ml of 0.091 m naoh at 25oc? hcl (aq) + naoh (aq) → nacl (aq) + h2o (l) ?

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  1. 17 November, 08:03
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    The acid base reaction equation is as follows;

    HCl + NaOH - - - > NaCl + H₂O

    stoichiometry of HCl to NaOH is 1:1

    NaOH is a strong base and HCl is a strong acid they completely dissociate into its ions

    number of HCl moles - 0.16 mol/L x 0.200 L = 0.032 mol

    number of NaOH moles - 0.091 mol/L x 0.300 L = 0.0273 mol

    Limiting reactant is NaOH therefore number of HCl moles reacted - 0.0273 mol

    the excess amount of HCl moles are - 0.032 - 0.0273 = 0.0047 mol

    since HCl is a strong acid

    total volume - 200 mL + 300 mL = 500 mL

    [HCl ] = [H⁺]

    therefore [H⁺] = 0.0047 mol / 0.500 mL

    [H⁺] = 0.0094 mol/L

    hydroxide ion concentration - 0.0094 M
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