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28 August, 05:33

How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa) ?

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  1. 28 August, 06:01
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    To solve this question, we will simply use the gas law which is as follows:

    PV = nRT where:

    P is the pressure = 100 kPa = 0.986923 atm

    V is the volume = 6.8 liters

    n is the required number of moles

    R is the gas constant = 0.08206

    T is the temperature = 25 degree celcius (room temp) = 298 kelvin

    Substitute in the above equation to get the number of moles as follows:

    0.986923 x 6.8 = n x 0.08206 x 298

    n = 0.2744 moles
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