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29 October, 09:13

How many equivalents are present in 5.0 g of al3+?

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  1. 29 October, 12:51
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    The one definition of an equivalent weight that I know is that it is the amount of electrons which a substance gains or loses per mole.

    Al3 + has + 3 charge therefore it loses 3 e-, so we can say that there are 3 equivalent weights in 1 mol Al3+.

    1 mol Al3 + = 3 eq. wts.

    1 mol Al x (27 g / 1 mol) x (1 mol / 3 eq. wts.) = 9.0 g = 1 eq. wt.

    Answer:

    5.0 g Al3 + x (1 eq. wt. / 9.0 g) = 0.56 eq. wts.
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