MnO2 + 4HCL--->MnCl2+Cl2+2H2O:

If 0.86 mole of MnO2 and 48.2g of HCL react, which reagent will be used up first? How many grams of Cl2 will be produced?

We are given with two amounts of the reactants and is asked to determine which of the two is the limiting reactant. In this case, we just have to convert the mass of HCL first and divide by 4. The answer is 0.33. Hence, HCl is used up first. The grams of Cl2 produced is 23.43 grams