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20 November, 02:22

What is the empirical formula of a substance that is 53.5% C, 15.5% H, 31.1% N?

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  1. 20 November, 04:33
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    For each carbon, hydrogen and nitrogen. You have to divide each percentage by its atomic mass.

    C = 53.5/12.0107 = 4.45436

    H = 15.5/1.00794 = 15.377899

    N = 31.1/14.0067 = 2.220365

    Round the number to significant figures

    C = 4.45

    H = 15.4

    N = 2.22

    Divide Each Number by the smallest number out of the three

    so N = 2.22/2.22 = 1

    H = 15.4/2.22 = 6.9 = 7

    C = 4.45/2.22 = 2

    So the Formula Should Be C2H7N
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