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18 April, 12:21

The composition of a compound is 20.01% carbon and 79.99% oxygen by mass. what is its empirical formula?

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  1. 18 April, 15:55
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    Assume there are 100g of the compound.

    Mass of carbon:20.01g

    Mass of oxygen:79.99g

    Number of mole of carbon:20.01/12=1.6675mol

    Number of mole of oxygen:79.99/32=2.4996875mol

    Mole ratio between carbon and oxygen:

    1.6675/1.6675:2.4996875/1.6675

    =1:1.499062969

    1x2:1.499062969x2

    =2:2.998125937

    ≈2:3

    Hence, the empirical formula:

    C2O3
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