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9 January, 21:27

A pure compound is found to be 40.0% carbon by mass, 6.73% hydrogen by mass, and 53.3% oxygen by mass. determine the empirical formula of the compound. be sure to show your work.

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  1. 9 January, 23:12
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    Since there is no weight, I would assume that this is a 100g of pure compound.

    Okay so I would be changing the percentage to gram to solve for the mole.

    So

    40.0g C (1 mol C/12.01 g C) = 3.33 mol C

    6.73g H (1 mol H/1.01 g H) = 6.66 mol H

    53.3g O (1 mol O/16.00 g O) = 3.33 mol O

    With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
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