A snorkeler takes a syringe filled with 14mL of air from the surface, where the pressure is 1.0 atm, to an unknown depth. The volume of the air in the syringe at this depth is 8.5mL. a) What is the pressure at this depth? b) If the pressure increases by 1 atm for every additional 10 m of depth, how deep is the snorkeler?

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Chemistry

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29 May, 14:19

A snorkeler takes a syringe filled with 14mL of air from the surface, where the pressure is 1.0 atm, to an unknown depth. The volume of the air in the syringe at this depth is 8.5mL. a) What is the pressure at this depth? b) If the pressure increases by 1 atm for every additional 10 m of depth, how deep is the snorkeler?

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Jimenez · Answer 1

To answer the question above, we assume that the gas is ideal such that,

P1V1 = P2V2

Substitute the given values to the equation,

1 atm x 14 mL = P2 x 8.5 mL

The value of P2 from the equation is 1.64 atm.

B. The depth to where the snorkeler is,

(1.64 atm) x (10 m / 1 atm) - (1 atm) x (10 m / 1 atm) = 6.4 m

Thus, the snorkeler is 6.4 m deep into the sea.