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20 September, 11:34

How many moles of hydrogen atoms are present in 25.0 g of water?

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  1. 20 September, 12:07
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    M (H₂O) = 25.0 g

    M (H₂O) = 18.02 g/mol

    n (H₂O) = m (H₂O) / M (H₂O)

    n (H) = 2n (H₂O) = 2m (H₂O) / M (H₂O)

    n (H) = 2*25.0/18.02=2.775 mol
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