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15 October, 17:02

An ideal gas has a density of 1.10*10-6 g/cm3 at 1.00*10-3 atm and 80.0 ∘c. identify the gas.

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  1. 15 October, 17:50
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    From ideal gas equation that is pv = nRt

    n=number of moles which can be written as the ratio between the weight of a gas that is mass and its molecular mass n=m/Mm

    pv = (m/Mm) RT

    density is=mass per unit volume

    P=m/v by arranging the equation we get

    R = 0.082atm/mol/k

    Mm=pRT/P=[ (1.10 x10^-6 x1000g/l) xo. 082 atm/mol/k x (80+273] / (1.00 x10^-3) = 31.84 to the nearest ten is 32

    hence the gas is oxygen
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