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17 March, 00:59

Ammonia, NH3, is a common ingredient in many household cleaning agents. If you have a cleaning agent containing 2.07 mol NH3, how many grams of NH3 are in the cleaning agent?

I don't understand how to set this problem. I know to start with 2.07 then multiply up I'm stuck the rest of the way

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  1. 17 March, 03:14
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    In order to do this question you have to first know the relationship between moles (g) and mass (g); Mass = Mole * Molar Mass

    if mole of NH₃ = 2.07 mol

    and Molar Mass of NH₃ = [14 + (3 * 1) ] g/mol

    then mol = 2.07 mol * 17 g/mol

    = 35.19 g
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