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26 January, 13:43

How many moles of magnesium chloride (mgcl2) are in 1.31 l of 0.38 m mgcl2?

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  1. 26 January, 14:51
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    Molarity can be defined as the number of moles dissolved in 1 L of solution.

    The molarity of MgCl₂ is 0.38 mol/L

    In 1 L of MgCl₂ solution, amount go 0.38 moles is dissolved.

    Therefore in 1.31 L of MgCl₂ - 0.38 mol / 1 L x 1.31 L = 0.4978 mol rounded off is 0.50 mol

    In 1.31 L of solution, amount of 0.50 mol of MgCl₂ is present.
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