If a reaction mixture initially contains 0.195 m so2cl2, what is the equilibrium concentration of cl2 at 227? c?

Missing in your question the K constant value = 2.99X10^-7

The reaction equation:

SOCl2 ⇄ SO2 + Cl2

initial 0.195 0 0

-X + X + X

final (0.195-X) X X

K = [SO2][Cl2]/SOCl2

by substitution

2.99X10^-7 = (X) (X) / (0.195-X)

2.99X10^-7 = X^2 / (0.195-X) by solving this equation

∴X = 0.00024 = 2.4 X10^-4

∴[Cl2] = 2.4X10^-4 m