4 g of ag2so4 will dissolve in 1l of water. calculate the solubility product (ksp) for silver (i) sulfate.

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Chemistry

Kolten Cohen

6 November, 08:32

4 g of ag2so4 will dissolve in 1l of water. calculate the solubility product (ksp) for silver (i) sulfate.

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Krystal Parker · Answer 1

Reaction of dissociation: Ag₂SO₄ → 2Ag⁺ + SO₄²⁻.

m (Ag₂SO₄) = 4 g.

V (Ag₂SO₄) = 1 l.

n (Ag₂SO₄) = m (Ag₂SO₄) : M (Ag₂SO₄).

n (Ag₂SO₄) = 4 g : 311,8 g/mol.

n (Ag₂SO₄) = 0,0128 mol.

n (Ag⁺) = 2 · 0,0128 mol = 0,0256 mol.

n (Ag₂SO₄) = n (SO₄²⁻) = 0,0128 mol.

c (Ag⁺) = n : V = 0,0256 mol : 1 l = 0,0256 mol/l.

Ksp = c (Ag⁺) ² · c (SO₄²⁻).

Ksp = (0,0256 mol/l) ² · 0,0128 mol/l.

Ksp = 8,3·10⁻⁶.