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2 December, 22:59

1. How many milliliters of a 0.184 M NaNO3 solution contain 0.113 moles of NaNO3? ans:614 mL

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  1. 3 December, 01:10
    0
    C=0.184 mol/L

    n=0.113 mol

    n=CV

    V=n/C

    V=0.113/0.184=0.614 L = 614 mL
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