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3 June, 18:16

What is the concentration of nitrate ions in a 0.225 msr (no3) 2 solution?

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  1. 3 June, 20:10
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    We are given that there are 2 moles of NO3 from the 0.225 M Sr (NO3) 2 solution. Therefore we simply use stoichiometry to solve this problem.

    Concentration NO3 = 0.225 M Sr (NO3) 2 * (2 moles NO3 / 1 mole Sr (NO3) 2)

    Concentration NO3 = 0.45 M
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