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2 March, 18:23

A compound contains only c, h, and n. it is 58.51% c and 7.37% h by mass. helium effuses through a porous frit 3.20 times as fast as the compound does. determine the empirical and molecular formulas of this compound. (type your answer using the format c2h2n for c2h2n.

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  1. 2 March, 18:37
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    Let us assume that there are 100 grams of substance present. The masses of the constituents will be:

    C - 58.51 g

    H - 7.37 g

    N - 100 - 58.51 - 7.37 = 34.12 g

    Next, we determine the moles of each substance by dividing by the atomic masses:

    C - 58.51/12 = 4.88

    H - 7.37/1 = 7.37

    N - 34.12/14 = 2.44

    Dividing all of the moles by the lowest number of moles, which is 2.44 of nitrogen, we get the ratio:

    C - 2

    H - 3

    N - 1

    The empircal formula becomes C₂H₃N

    Next, we apply Graham's Law of diffusion, which mathematically is:

    v₁/v₂ = √M₂ / √M₁

    Let species 1 be helium, meaning v₁/v₂ = 3.2 and M₁ = 4

    3.2 = √M₂ / √4

    M₂ = 40.96

    The mass of the empircal formula was:

    12 * 2 + 1 * 3 + 14 = 41

    The empircal formula is the molecular formula as their masses are approximately the same. This compound is C₂H₃N
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