What is the ph of a neutral solution at a temperature where kw=8.0*10-14?

A neutral solution is when the H⁺ concentration is equal to OH⁻ concentration.

Since there are equal amounts of both H⁺ and OH⁻, solution is neither basic nor acidic, they both react to form water.

kw is the ionic product of water

kw = [H⁺][OH⁻]

kw = 8.0 x 10⁻¹⁴

since [H⁺]=[OH⁻]

kw = [H⁺]²

[H⁺] = √ (8x10⁻¹⁴)

[H⁺] = 2.82 x 10⁻⁷ M

pH is calculated using the following equation

pH = - log [H⁺]

pH = - log (2.82 x 10⁻⁷ M)

pH = 6.54