A sample of 0.500 moles of gas is placed in a container of volume of 2.50L. What is the pressure of the gas in ATM if the gas is at 25 degrees celcius

The pressure of gas at ATm is calculated using ideal gas equation

that is Pv = nRT

P = pressure = ?

v = volume = 2.5 l

n = moles = 0.500moles

T = temperature in kelvin = 25 + 273 = 298k

R = gas constant = 0.082 l. atm/k. mol

p is therefore = nRT/V

p = (0.5 mol x0.082 l. atm/k. mol x298k) / (2.5l) = 4.89 atm