Calculate the volume of oxygen required to burn 12.00 l of ethane gas, c2h6, to produce carbon dioxide and water, if the volumes of c2h6 and o2 are measured under the same conditions of temperature and pressure

The volume of oxygen required to burn 12.00 L ethane is calculated as follows

find the moles of C2H6 used

At STP 1 mole is always = 22.4 L, what about 12.00 L

= (12.00L x 1 moles) 22.4 L = 0.536 moles

write the reacting equation

2C2H6 + 7O2 = 4CO2 + 6H2O

by use of mole ratio between C2H6 : O2 which is 2:7 the moles of O2

= 0.536 x7/2 = 1.876 moles

again at STP 1mole = 22.4 L what about 1.876 moles

= 22.4 L x 1.876 moles / 1 mole = 42.02 L