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4 March, 23:47

Given an initial cyclopropane concentration of 0.00560 m, calculate the concentration of cyclopropane that remains after 1.50 hours.

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  1. 5 March, 03:20
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    We can solve this problem by assuming that the decay of cyclopropane follows a 1st order rate of reaction. So that the equation for decay follows the expression:

    A = Ao e^ ( - k t)

    Where,

    A = amount remaining at time t = unknown (what to solve for)

    Ao = amount at time zero = 0.00560 M

    k = rate constant

    t = time = 1.50 hours or 5400 s

    The rate constant should be given in the problem which I think you forgot to include. For the sake of calculation, I will assume a rate constant which I found in other sources:

    k = 5.29 * 10^-4 s-1 (plug in the correct k value)

    Plugging in the values in the 1st equation:

    A = 0.00560 M * e^ (-5.29 * 10^-4 s-1 * 5400 s)

    A = 3.218 * 10^-4 M (simplify as necessary)
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