There are 3.01 x 1023 atoms of gold, 1 mole of platinum, and 3.01 moles of silver. Which contains more atoms?

We are asked in this problem to determine which of the three elements with corresponding number of moles contains the most number of atoms. To answer this, we convert the number of moles to number of atoms by multiplying Avogadro's number (6.022 x 10^23) to them. For gold, there are 3.01 x 1023 atoms; for platinum, there are 6.022 x 10^23 atoms and for silver, there are 1.81x10^24 atoms. The answer is silver.