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Chemistry
Damari Byrd
1 April, 09:32
How many molecules are in 79g of fe2o3
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Jaylynn Sampson
1 April, 09:40
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Convert grams - > mols and then mols - > atoms
We know that there are 6.02 x 10^23 atoms/mol
And we know that there are about 160 grams of fe2o3 per mol
So (79g fe2o3) / (160 g/mol) =.49 mol fe2o3
Now we use avogadro’s number to do
(.49 mol fe2o3) / (6.02 x 10^23 atoms/mol) = the answer.
I’ll leave the easy math to you.
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