Ask Question
17 May, 11:40

How many oxygen molecules are in 22.4 liters of oxygen gas at 273k and 101.3kpa?

+4
Answers (1)
  1. 17 May, 15:02
    0
    How many oxygen molecules are in 22.4 liters of oxygen gas at 273k and 101.3kpa

    First solve the number of moles of the oxygen gas by using the ideal gas equation:

    PV = nRT

    Where n is the number of moles

    n = PV/RT

    n = (101 300 Pa) (22.4 L) (1 m3/1000 L) / (8.314 Pa m3 / mol K) (273 K)

    n = 1 mol O2

    the number of molecules can be solve using avogrados number 6.022x10^23 molecule / mole

    molecules of one mole O2 = 6.022x 10^23 molecules
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many oxygen molecules are in 22.4 liters of oxygen gas at 273k and 101.3kpa? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers