Ask Question
4 March, 22:34

How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the density of iron is 7.87 g/mL? Show all steps of your calculation as well as the final answer. Fe + HNO3 → Fe (NO3) 3 + H2

+3
Answers (1)
  1. 5 March, 01:34
    0
    Balance the equation first:

    2 Fe+6 HNO3→2 Fe (NO3) 3+3H2

    Then calculate mass of Iron:

    4.5*3.0*3.5 cm3 (1 mL1 cm3) (7.87 g Fe1 ml) = 371.86 g Fe

    Now use Stoichiometry:

    371.86 g Fe * (1 mol Fe55.85 g Fe) * (6 mol HNO32 mol Fe) = 19.97 mol HNO3

    Convert moles of nitric acid to grams

    19.97 mol HNO3 * (63.01 g HNO31 mol HNO3) = 1258.3 g HNO3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the density of iron ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers