The complete combustion of octane, C8H18, the main component of gasoline, proceeds as follows: 2C8H18 (l) + 25 O2 (g) - - > 16 CO2 (g) + 18 H2O (g)

a. How many moles of 02 are needed to burn 1.50 mol of C8H18?

b. How many grams of 02 are needed to burn 10.0 g of C8H18?

c. Octane has a density of 0.692 g/ml at 20 degrees Celsius. How many grams of 02 are required to burn 15.0 gal of C8H18 (the capacity of an average file tank) ?

Question

Cricket

19 March, 00:39

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Answers (1)

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Mitch · Answer 1

The ratio of mole number of the reactants and products is equal to the coefficients. So the answer is a. 18.75 mol. b. 35.1 g. c. 1.38 * 10^5 g.