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8 April, 22:09

Which equation is set up correctly to determine the volume of a 3.2 mole sample of oxygen gas at 50°C and 101.325 kPa?

A V = (3.2 mol) (8.314 L⋅kPa/K⋅mol) (323 K) 101.325 kPa

B V = (3.2 mol) (8.314 L⋅kPa/K⋅mol) (50∘C) 1 atm

C V = (8.314 L⋅kPa/K⋅mol) (50∘C) (3.2 mol) (101.325 kPa)

D V = (3.2 mol) (8.314 L⋅kPa/K⋅mol) (1 atm) (323 K)

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  1. 9 April, 00:53
    0
    N = 3.2 moles, T = 50 + 273 = 323 K, P = 101.325 kPa, R = 8.314 L. kPa/K. mol

    PV = nRT

    V = nRT / P substituting.

    V = (3.2 mole) (8.314 L. kPa/K. mol) (323 K) / (101.325 kPa)

    That is the answer, but it is not among the options you provided. Check your options properly.
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