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4 August, 17:06

The oxygen gas produced in part a has a density of 1.43g/l. calculate the volume of of the o2 gas produced pg 76

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  1. 4 August, 17:19
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    The following is missing from the task above:

    LiClO4 (s) →LiCl (s) + 2O2 (g)

    m (LiClO4) = 100g

    a) m (O2) = ?

    From the reaction we got the following number of moles ratio:

    n (LiClO4) : n (02) = 1 : 2

    So, from the ratio, we can determine number of moles from O2:

    n (02) = n (LiClO4) x 2 = (m/M) x 2 = 100/106.4 x 2 = 1.9 mole

    Now we can calculate the mass of oxygen:

    m (O2) = n x M = 1.9 x 32 = 60.15 g

    b) V (O2) = ?

    Now when we have the value of the mass of oxygen, we can calculate its volume with density equation:

    d (O2) = m (O2) / V (O2) ⇒ V (O2) = m (O2) / d (O2)

    V (O2) = 60.15 / 1.43

    V (02) = 42.06 L
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