Ask Question
1 November, 22:29

How many milliliters of 0.564 m hcl are required to react with 6.03 grams of caco3?

+1
Answers (1)
  1. 2 November, 01:34
    0
    First write up a balanced equation

    CaCO3 + 2 HCl = CO2 + CaCl2 + H2O

    Find how many moles of CaCO3 you are dealing with

    6.03 g x 1 mol / 100 g =.0603 moles

    However, you need twice as much HCl

    .0603 x 2 moles /.564 M =.21 L
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many milliliters of 0.564 m hcl are required to react with 6.03 grams of caco3? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers