How much heat energy is absorbed when 6.83 kg of water is heated from 10.0 0C to 47.0 0C. The specific heat of water is 4.184 J/g 0C.

Question

Chemistry

Mallory Gutierrez

31 July, 21:30

How much heat energy is absorbed when 6.83 kg of water is heated from 10.0 0C to 47.0 0C. The specific heat of water is 4.184 J/g 0C.

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Orlando Hooper · Answer 1

Heat energy = mass x specific heat x change in temperature

change in temperature=47.0=10.0 = 37 degrees

convert mass in G = 6.83x1000=6830g

Heat energy is hence = 6830 x 4.184 j/g/degrees x 37=1057338.64 j or 1057.33864Kj