If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0°C to 97.0°C, what mass is the sample of aluminum? (The specific heat of aluminum is 0.90 J / (g * °C).) 0.10 g 10.0 g 12.0 g 57.7 g

Given:

The energy required is

Q = 832 J

The temperature rise is

ΔT = 97 - 20 C

= 77 C = 77 K

The specific heat is

c = 0.9 J / (g-C)

= (0.9 J / (g-K) * (1000 g/kg)

= 900 J / (kg-K)

Let the mass be m kg.

Then

(m kg) * (c J / (kg-K)) * (ΔT K) = (Q J)

or

900*77*m = 832

m = 0.012 kg = 12 g

Answer: The mass of aluminum is 12.0 g