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26 November, 08:33

Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.

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  1. 26 November, 12:00
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    From idea gas equation that is PV=nRT

    T = temperature in kelvin

    R=gas cosntant (0.0821atm/k/mol)

    P=pressure (3.5atm)

    V=volume 3.30L

    n=number of moles (2.20mole)

    T is therefore = PV/nR

    T={ (3.50 x3.30) / (2.20 x 0.0821) }=63.95k
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