Silver chloride, often used in silver plating, contains 75.27% ag. part a calculate the mass of silver chloride required to plate 135 mg of pure silver.

179.35 mg of silver chloride is required to plate 135 mg of silver. Create an expression showing what you know. Namely that 75.27% of X is equal to 135. So we get 75.27% X = 135 0.7527 X = 135 Now divide both sides by 0.7527 X = 135 mg / 0.7527 = 179.3543 mg So it will take 179.35 mg of silver chloride to plate out 135 mg of pure silver.