How many moles of MgS2O3 are there in 205 g of the compound?

Question

Chemistry

Taylor Morgan

5 May, 23:43

How many moles of MgS2O3 are there in 205 g of the compound?

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Jake Mahoney · Answer 1

First, caluclate the formula mass of Mg S2O3. This is add the masses of each element in the formula. Mg: 24.3 g/mol. S: 2 * 32.1 g/mol = 64.2 g/mol. O: 3 * 16 g/mol = 48 g/mol = > formula mass = 24.3 g/mol + 64.2 g/mol + 48 g/mol = 136.5 g/mol. Second, calculate the number of moles using number of moles = mass in grams / formula mass = 205 g / 136.5 g/mol = 1.5 moles. Anser: 1.5 moles