What is the volume in milliliters of 350 m koh needed to completely neutralize 15.0 ml of

a. 250 m h2so4 solution?

To answer this question you need to know the equation of both reactions. For every KOH there will be 1 OH - ion, but for every H2SO4 there will be 2 H + ion. That means one molecule of H2SO4 will neutralize 2 KOH. Then, the amount of H2SO4 needed should be:

250m/350m * 15ml*2 = 21.42 ml