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18 March, 14:27

How much h2 gas at stp can be produced by the reaction 2 na (s) + 2 h2o (ℓ) - → h2 (g) + 2 naoh (aq) of 4.40 g of na and excess water? answer in units of l?

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  1. 18 March, 18:10
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    From the reaction;

    2Na (s) + 2 H2O (l) = H2 (g) + 2 NaOH (aq)

    The atomic mass of sodium is 22.99 g/mol

    The number of moles of sodium will be

    = 4.40/22.99

    = 0.1914 moles

    The mole ratio of sodium and hydrogen is 2: 1

    ; therefore, the number of moles of hydrogen = 0.1914 / 2

    = 0.0957 moles

    1 mole of hydrogen at s. t. p occupies 22.4 liters, hence 0.0957 moles will occupy; 0.0957 * 22.4 = 2.144 L

    Therefore, 2.144 liters of hydrogen gas will be produced
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