For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.

Question

Chemistry

Edgar Ayers

13 April, 01:09

For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.

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Lizbeth · Answer 1

Data Given:

Change in Entropy = ΔH = 120.5 kJ = 1.20 * 10⁵ J

Temperature = T = 298 K

Change in Entropy = ΔS = 758.2 J/K

Using Formula,

ΔG = ΔH - T ΔS

Putting Values,

ΔG = (1.20 * 10⁵ J) - (298 K * 758.2 J/K)

ΔG = - 1.059 * 10⁵ J

ΔG = - 105.94 kJ