What is the percent cr, by mass, in the steel sample? express your answer numerically as a percentage?

Given:3.40g sample of the steel used to produce 250.0 mLSolution containing Cr2O72-

Assuming all the Cr is contained in the BaCrO4 at the end.

(0.145 g BaCrO4) / (253.3216 g BaCrO4/mol) x (250.0 mL / 10.0 mL) x (1 mol Cr / 1 mol BaCrO4) x (51.99616 g Cr/mol / (3.40 g) = 0.219 = 21.9% Cr