Part complete the first-order reaction, 2 n2o (g) → 2 n2 (g) + o2 (g), has a rate constant equal to 0.76 s-1 at 1000 k. how long will it take for the concentration of n2o to decrease to 32 % of its initial concentration?

Question

Chemistry

Henry

16 May, 13:10

Part complete the first-order reaction, 2 n2o (g) → 2 n2 (g) + o2 (g), has a rate constant equal to 0.76 s-1 at 1000 k. how long will it take for the concentration of n2o to decrease to 32 % of its initial concentration?

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Cannon Gallagher · Answer 1

The time taken for the concentration of N2O to decrease to 32% of its initial concentration is calculated as follows

In (A1/A0) = - Kt

A1 = final concentration = 32/100=0.32

A0 = initial concentration = 100/1000=1

K = constant = 0.76 per sec

time is therefore calculated as follows

In (0.32/1) = - 0.76 t

-1.1394 = - 0.76t divide both sid3es by - 0.76

t is therefore = 1.5 s