A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas?

We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant, 0.08206 Latm/Kmol

T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT

T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm) (10.0 L) / (3.00 mol) (0.08206 Latm/Kmol)

T = 183 K

The temperature of the gas is 183 K.