Ask Question
24 March, 20:27

In the following reaction, 451.4 g of lead reacts with excess oxygen forming 365.0 g of lead (II) oxide. Calculate the percent yield of the reaction.

+3
Answers (1)
  1. 24 March, 20:51
    0
    Let MM (x) be the molar mass of x.

    MM (Pb) : MM (PbO)

    =207.21 : 223.20 = 451.4 g : x g

    cross multiply and solve for x

    x=223.2/207.21*451.4

    = 486.23 g

    Percentage yield = 365.0/486.23 = 0.75067 = 75.07% (rounded to 4 sign. fig.)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In the following reaction, 451.4 g of lead reacts with excess oxygen forming 365.0 g of lead (II) oxide. Calculate the percent yield of the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers