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12 March, 03:36

A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 305 mL of solution. How many moles of ammonium chloride are present in the resulting solution?

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  1. 12 March, 05:45
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    Reacting mass=11.0

    molar mass = 53.45

    moles=reacting Mass / molar mass

    11.0/53.45=0.21moles
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