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20 February, 19:35

How many moles of HNO3 are present if 2.50*10-2 mol of Ba (OH) 2 was needed to neutralize the acid solution?

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  1. 20 February, 20:16
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    2HNO₃ + Ba (OH) ₂ = Ba (NO₃) ₂ + 2H₂O

    2 mol HNO₃ - 1 mol Ba (OH) ₂

    x mol HNO₃ - 2.50*10⁻² mol Ba (OH) ₂

    x=2.50*10⁻²*2/1=0.05 mol
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